A DNA polymorphism close to the gene CYP1A1 has two alleles, 1 and 2. Possession of at lowest one copy of allele 2 makes a personality particularly sensitive to the carcinogenic effects of cigarette smoke. The frequency of allele 2 is 0.1. From this integer we predict that, for this reason, 19% of population in the population will be at an elevated risk of developing cancer from smoking.
Can u afford an explanation please.
Thank you
Answer:
Each of us has two alleles of the CYP1A1 gene (one allele form respectively parent). Therefore, we each own a 10% chance (0.1) of have at least one allele from respectively parent with the polymorphism. Since we hence have TWO probability of having one allele, we own 0.1 plus 0.1 chances of at lowest one allele. This would equal a total of 0.2 (20%) chance of at lowest possible one allele.
Since we have a 1% unpredictability of having both alleles near the polymorphism (0.1 X 0.1 = 0.01 = 1%), we need to subtract this 'redundancy of risk' from our 20% accident. This yields a final risk of 20% - 1% = 19%.
Hope this help. Best wishes and good luck.
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