Paternity try-out?
how this is done and what is its principle to work
and more importantly
I bring a case resembling this
mother is disease carrier(Dd) and father is normal(dd)
for a mandelian inherited disease
but their girl is diseased (dd)
and paternity oral exam said girl is from them
how to explain this
Answers:
A paternity test is a trial to see if the man who claims to be the father really is the father. For your problem, that's all the detail vital. However, your problem is incorrect. If father is dd normal, later the daughter is either dd mundane or DD diseased. If she is DD diseased, then it is because of a spontaneous mutation.
If she is dd usual, then this is the mode it works:
-- d d
D Dd Dd
d dd dd
See, the child gets one allele (d or D) from dad (top) and one from mom (side). There are 4 possibilities: 2 are Dd (carriers) and 2 are dd (normal), so there's a 50% hit and miss that the girl is normal and 50% she's a owner. If she's DD diseased, then here are two possibilities-- 1. Dad is not really dad. 2. There was a mutation within the creation of the egg that sent a diseased allele to match beside a diseased allele from the mom.
How do you test your hypothesis? 1. Repeat paternity trial. 2. Breed the girl with a boy who's a delivery service and see what percentage of the children would be diseased (should be 50%). but testing choice 2 would cart a little bit of time if you're in actual fact talking roughly human beings.
EDIT:
If DD x Dd, how do you get dd?
One more possibility: It's really an X-linked recessive gene, and the daughter have turner's syndrome (45x): getting d0, making it a disease state.
dunno
paternity test is to find who's the father
A child get one gene from each parent, so these citizens could have a Dd child or a DD child.
There's no object to doubt the paternity test.
Edited for capitalization.
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